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For the function 
f(x)=x^(2)+5x+4, find the slope of the secant line between 
x=-8 and 
x=1.
Answer:

For the function f(x)=x2+5x+4 f(x)=x^{2}+5 x+4 , find the slope of the secant line between x=8 x=-8 and x=1 x=1 .\newlineAnswer:

Full solution

Q. For the function f(x)=x2+5x+4 f(x)=x^{2}+5 x+4 , find the slope of the secant line between x=8 x=-8 and x=1 x=1 .\newlineAnswer:
  1. Use Slope Formula: To find the slope of the secant line between two points on a function, we use the formula for slope, which is the change in yy-values divided by the change in xx-values. This is also known as the difference quotient. The formula is (f(x2)f(x1))/(x2x1)(f(x_2) - f(x_1)) / (x_2 - x_1), where x1x_1 and x2x_2 are the xx-values of the two points.
  2. Find f(8)f(-8): First, we need to find the y-value for x=8x = -8 by plugging it into the function f(x)=x2+5x+4f(x) = x^2 + 5x + 4. This gives us f(8)=(8)2+5(8)+4f(-8) = (-8)^2 + 5(-8) + 4.
  3. Find f(1)f(1): Calculating f(8)f(-8), we get f(8)=6440+4=28f(-8) = 64 - 40 + 4 = 28.
  4. Identify Two Points: Next, we need to find the yy-value for x=1x = 1 by plugging it into the function f(x)=x2+5x+4f(x) = x^2 + 5x + 4. This gives us f(1)=(1)2+5(1)+4f(1) = (1)^2 + 5(1) + 4.
  5. Calculate Slope: Calculating f(1)f(1), we get f(1)=1+5+4=10f(1) = 1 + 5 + 4 = 10.
  6. Calculate Slope: Calculating f(1)f(1), we get f(1)=1+5+4=10f(1) = 1 + 5 + 4 = 10.Now we have the two points on the function: (8,28)(-8, 28) and (1,10)(1, 10). We can use these to find the slope of the secant line using the formula f(x2)f(x1)x2x1\frac{f(x_2) - f(x_1)}{x_2 - x_1}.
  7. Calculate Slope: Calculating f(1)f(1), we get f(1)=1+5+4=10f(1) = 1 + 5 + 4 = 10.Now we have the two points on the function: (8,28)(-8, 28) and (1,10)(1, 10). We can use these to find the slope of the secant line using the formula (f(x2)f(x1))/(x2x1)(f(x_2) - f(x_1)) / (x_2 - x_1).The slope of the secant line is (f(1)f(8))/(1(8))=(1028)/(1(8))=(18)/9(f(1) - f(-8)) / (1 - (-8)) = (10 - 28) / (1 - (-8)) = (-18) / 9.
  8. Calculate Slope: Calculating f(1)f(1), we get f(1)=1+5+4=10f(1) = 1 + 5 + 4 = 10.Now we have the two points on the function: (8,28)(-8, 28) and (1,10)(1, 10). We can use these to find the slope of the secant line using the formula (f(x2)f(x1))/(x2x1)(f(x_2) - f(x_1)) / (x_2 - x_1).The slope of the secant line is (f(1)f(8))/(1(8))=(1028)/(1(8))=(18)/9(f(1) - f(-8)) / (1 - (-8)) = (10 - 28) / (1 - (-8)) = (-18) / 9.Calculating the slope, we get 18/9=2-18 / 9 = -2.

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