For the function f(x)=-x^(2)+4x-8, find the slope of the secant line between x=2 and x=5. Answer:

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For the function  f(x)=-x^(2)+4x-8, find the slope of the secant line between  x=2 and  x=5. Answer:

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Define Slope Formula: To find the slope of the secant line between two points on a function, we use the formula for slope, which is the change in y divided by the change in x, or (f(x2) - f(x1)) / (x2 - x1). Here, x1 = 2 and x2 = 5.Find f(2): First, we need to find the value of the function at x = 2. We substitute x = 2 into the function f(x) = -x^2 + 4x - 8 to get f(2) = -(2)^2 + 4(2) - 8.Calculate f(2): Calculating f(2) gives us f(2) = -4 + 8 - 8 = -4.Find f(5): Next, we need to find the value of the function at x = 5. We substitute x = 5 into the function f(x) = -x^2 + 4x - 8 to get f(5) = -(5)^2 + 4(5) - 8.Calculate f(5): Calculating f(5) gives us f(5) = -25 + 20 - 8 = -13.Calculate Slope: Now we have the function values at both points: f(2) = -4 and f(5) = -13. We can use these to find the slope of the secant line: slope = (f(5) - f(2)) / (5 - 2).Substitute Values: Substituting the values we found, the slope is (-13 - (-4)) / (5 - 2) = (-13 + 4) / 3 = -9 / 3.Final Slope Calculation: Calculating the slope gives us -9 / 3 = -3.

For the function $f(x)=-x^{2}+4 x-8$ , find the slope of the secant line between $x=2$ and $x=5$ . $\newline$ Answer:

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For the function f(x)=−x2+4x−8 f(x)=-x^{2}+4 x-8 f(x)=−x2+4x−8, find the slope of the secant line between x=2 x=2 x=2 and x=5 x=5 x=5.\newlineAnswer:

For the function $f(x)=-x^{2}+4 x-8$ , find the slope of the secant line between $x=2$ and $x=5$ . $\newline$ Answer: