For the function f(x)=x^(2)+4x-1, find the slope of the secant line between x=-3 and x=-1. Answer:

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For the function  f(x)=x^(2)+4x-1, find the slope of the secant line between  x=-3 and  x=-1. Answer:

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Slope Formula: To find the slope of the secant line between two points on a function, we use the formula for slope, which is the change in y divided by the change in x (rise over run). This is given by (f(x2) - f(x1)) / (x2 - x1), where x1 and x2 are the x-values of the two points.Find y for x=-3: First, we need to find the y-value for x = -3 by substituting -3 into the function f(x) = x^2 + 4x - 1. This gives us f(-3) = (-3)^2 + 4(-3) - 1 = 9 - 12 - 1 = -4.Find y for x=-1: Next, we need to find the y-value for x = -1 by substituting -1 into the function f(x) = x^2 + 4x - 1. This gives us f(-1) = (-1)^2 + 4(-1) - 1 = 1 - 4 - 1 = -4.Identify Two Points: Now we have the two points on the function: (-3, f(-3)) = (-3, -4) and (-1, f(-1)) = (-1, -4). We can see that the y-values for both points are the same, which means the slope of the secant line is 0 because there is no change in y.Calculate Slope: The slope of the secant line is therefore (f(-1) - f(-3)) / (-1 - (-3)) = (-4 - (-4)) / (-1 + 3) = 0 / 2 = 0.

For the function $f(x)=x^{2}+4 x-1$ , find the slope of the secant line between $x=-3$ and $x=-1$ . $\newline$ Answer:

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For the function f(x)=x2+4x−1 f(x)=x^{2}+4 x-1 f(x)=x2+4x−1, find the slope of the secant line between x=−3 x=-3 x=−3 and x=−1 x=-1 x=−1.\newlineAnswer:

For the function $f(x)=x^{2}+4 x-1$ , find the slope of the secant line between $x=-3$ and $x=-1$ . $\newline$ Answer: