For the function f(x)=-x^(2)-2x+5, find the slope of the secant line between x=-4 and x=2. Answer:

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For the function  f(x)=-x^(2)-2x+5, find the slope of the secant line between  x=-4 and  x=2. Answer:

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Calculate y-value for x = -4: To find the slope of the secant line between two points on a function, we use the formula for slope, which is the change in y-values divided by the change in x-values. This is given by the formula (f(x2) - f(x1)) / (x2 - x1), where x1 and x2 are the x-values of the two points.Calculate y-value for x = 2: First, we need to find the y-value for x = -4 by substituting -4 into the function f(x) = -x^2 - 2x + 5. This gives us f(-4) = -(-4)^2 - 2(-4) + 5.Find slope using y-values: Calculating f(-4) gives us f(-4) = -(16) + 8 + 5 = -16 + 8 + 5 = -8 + 5 = -3.Identify horizontal secant line: Next, we need to find the y-value for x = 2 by substituting 2 into the function f(x) = -x^2 - 2x + 5. This gives us f(2) = -(2)^2 - 2(2) + 5.Determine slope of horizontal line: Calculating f(2) gives us f(2) = -(4) - 4 + 5 = -4 - 4 + 5 = -8 + 5 = -3.Now we have both y-values: f(-4) = -3 and f(2) = -3. We can use these to find the slope of the secant line. However, we notice that the y-values are the same, which means the secant line is horizontal.The slope of a horizontal line is 0. Therefore, the slope of the secant line between x = -4 and x = 2 for the function f(x) is 0.

For the function $f(x)=-x^{2}-2 x+5$ , find the slope of the secant line between $x=-4$ and $x=2$ . $\newline$ Answer:

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For the function f(x)=−x2−2x+5 f(x)=-x^{2}-2 x+5 f(x)=−x2−2x+5, find the slope of the secant line between x=−4 x=-4 x=−4 and x=2 x=2 x=2.\newlineAnswer:

For the function $f(x)=-x^{2}-2 x+5$ , find the slope of the secant line between $x=-4$ and $x=2$ . $\newline$ Answer: