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For the function 
f(x)=x^(2)-11, find the slope of the tangent line at 
x=12.
Answer:

For the function f(x)=x211 f(x)=x^{2}-11 , find the slope of the tangent line at x=12 x=12 .\newlineAnswer:

Full solution

Q. For the function f(x)=x211 f(x)=x^{2}-11 , find the slope of the tangent line at x=12 x=12 .\newlineAnswer:
  1. Calculate Derivative: To find the slope of the tangent line at a specific point on the graph of a function, we need to calculate the derivative of the function at that point. The derivative of a function at a point gives us the slope of the tangent line to the function at that point.
  2. Apply Power Rule: The function given is f(x)=x211f(x) = x^2 - 11. To find the derivative of this function, we use the power rule, which states that the derivative of xnx^n is nx(n1)n\cdot x^{(n-1)}. So, the derivative of x2x^2 is 2x(21)=2x2\cdot x^{(2-1)} = 2x.
  3. Evaluate Derivative at x=12x=12: Now we need to evaluate the derivative at x=12x = 12 to find the slope of the tangent line at that point. We substitute xx with 1212 in the derivative we found, which is 2x2x. So, the slope at x=12x = 12 is 2×122\times 12.
  4. Calculate Slope at x=12x=12: Calculating the slope at x=12x = 12 gives us 2×12=242\times 12 = 24. Therefore, the slope of the tangent line to the function f(x)=x211f(x) = x^2 - 11 at x=12x = 12 is 2424.

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