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For the function 
f(x)=x^(2)-10, find the slope of the tangent line at 
x=7.
Answer:

For the function f(x)=x210 f(x)=x^{2}-10 , find the slope of the tangent line at x=7 x=7 .\newlineAnswer:

Full solution

Q. For the function f(x)=x210 f(x)=x^{2}-10 , find the slope of the tangent line at x=7 x=7 .\newlineAnswer:
  1. Identify Function and Point: Identify the function and the point at which we need to find the slope of the tangent line.\newlineWe are given the function f(x)=x210f(x) = x^2 - 10 and we need to find the slope of the tangent line at x=7x = 7.
  2. Recall Tangent Line Slope: Recall that the slope of the tangent line to a function at a given point is the derivative of the function evaluated at that point.\newlineTo find the slope of the tangent line at x=7x = 7, we need to find the derivative of f(x)f(x) with respect to xx and then evaluate it at x=7x = 7.
  3. Calculate Derivative: Calculate the derivative of f(x)=x210f(x) = x^2 - 10 with respect to xx. The derivative of x2x^2 with respect to xx is 2x2x, and the derivative of a constant is 00. Therefore, the derivative of f(x)f(x) is f(x)=2xf'(x) = 2x.
  4. Evaluate at x=7x = 7: Evaluate the derivative at x=7x = 7 to find the slope of the tangent line at that point.\newlinef(7)=2×7=14f'(7) = 2 \times 7 = 14
  5. Conclude Slope is 1414: Conclude that the slope of the tangent line to the function f(x)f(x) at x=7x = 7 is 1414.

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