Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

For the function 
f(x)=-7x^(2)+3x-5, find the slope of the tangent line at 
x=3.
Answer:

For the function f(x)=7x2+3x5 f(x)=-7 x^{2}+3 x-5 , find the slope of the tangent line at x=3 x=3 .\newlineAnswer:

Full solution

Q. For the function f(x)=7x2+3x5 f(x)=-7 x^{2}+3 x-5 , find the slope of the tangent line at x=3 x=3 .\newlineAnswer:
  1. Find Derivative: To find the slope of the tangent line to the function at a specific point, we need to find the derivative of the function, which gives us the slope of the tangent line at any point xx. The function is f(x)=7x2+3x5f(x) = -7x^2 + 3x - 5. We will use the power rule for differentiation, which states that the derivative of xnx^n is nx(n1)n\cdot x^{(n-1)}.
  2. Apply Power Rule: Differentiate the function with respect to xx. The derivative of 7x2-7x^2 is 14x-14x (using the power rule, bringing down the exponent 22 and subtracting 11 from the exponent). The derivative of 3x3x is 33 (since the derivative of xx is 11). The derivative of a constant, 5-5, is 7x2-7x^200 (since constants do not change and their derivative is always 7x2-7x^200). So, the derivative 7x2-7x^222 is 7x2-7x^233.
  3. Evaluate at x=3x=3: Now we need to evaluate the derivative at x=3x = 3 to find the slope of the tangent line at that point.\newlineSubstitute x=3x = 3 into the derivative f(x)=14x+3f'(x) = -14x + 3.\newlinef(3)=14(3)+3=42+3=39f'(3) = -14(3) + 3 = -42 + 3 = -39.
  4. Calculate Slope: The slope of the tangent line at x=3x = 3 is 39-39.

More problems from Find the slope of a tangent line using limits