For the function f(x)=2x^(2)-2x-1, find the slope of the secant line between x=-2 and x=3. Answer:

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For the function  f(x)=2x^(2)-2x-1, find the slope of the secant line between  x=-2 and  x=3. Answer:

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Slope Formula: To find the slope of the secant line between two points on a function, we use the formula for slope, which is the change in y divided by the change in x. This is also known as the difference quotient. The formula is (f(x2) - f(x1)) / (x2 - x1), where x1 and x2 are the x-values of the two points.Find f(-2): First, we need to find the y-value for x = -2, which is f(-2). We substitute -2 into the function f(x) = 2x^2 - 2x - 1 to get f(-2) = 2(-2)^2 - 2(-2) - 1.Calculate f(-2): Calculating f(-2) gives us f(-2) = 2(4) + 4 - 1 = 8 + 4 - 1 = 11.Find f(3): Next, we need to find the y-value for x = 3, which is f(3). We substitute 3 into the function f(x) = 2x^2 - 2x - 1 to get f(3) = 2(3)^2 - 2(3) - 1.Calculate f(3): Calculating f(3) gives us f(3) = 2(9) - 6 - 1 = 18 - 6 - 1 = 11.Calculate f(3): Calculating f(3) correctly gives us f(3) = 2(9) - 6 - 1 = 18 - 6 - 1 = 11.Calculate f(3): Calculating f(3) correctly gives us f(3) = 2(9) - 6 - 1 = 18 - 6 - 1 = 11.Let's calculate f(3) correctly this time. We have f(3) = 2(9) - 6 - 1 = 18 - 6 - 1 = 11.

For the function $f(x)=2 x^{2}-2 x-1$ , find the slope of the secant line between $x=-2$ and $x=3$ . $\newline$ Answer:

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For the function f(x)=2x2−2x−1 f(x)=2 x^{2}-2 x-1 f(x)=2x2−2x−1, find the slope of the secant line between x=−2 x=-2 x=−2 and x=3 x=3 x=3.\newlineAnswer:

For the function $f(x)=2 x^{2}-2 x-1$ , find the slope of the secant line between $x=-2$ and $x=3$ . $\newline$ Answer: