Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

For the following quadratic equation, find the discriminant.

x^(2)-12 x+70=0
Answer:

For the following quadratic equation, find the discriminant.\newlinex212x+70=0 x^{2}-12 x+70=0 \newlineAnswer:

Full solution

Q. For the following quadratic equation, find the discriminant.\newlinex212x+70=0 x^{2}-12 x+70=0 \newlineAnswer:
  1. Identify coefficients: Identify the coefficients of the quadratic equation.\newlineThe standard form of a quadratic equation is ax2+bx+c=0ax^2 + bx + c = 0. In the given equation, x212x+70=0x^2 - 12x + 70 = 0, the coefficients are:\newlinea = 11 (coefficient of x2x^2)\newlineb = 12-12 (coefficient of xx)\newlinec = 7070 (constant term)
  2. Recall discriminant formula: Recall the formula for the discriminant of a quadratic equation. The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by the formula D=b24acD = b^2 - 4ac.
  3. Substitute coefficients: Substitute the identified coefficients into the discriminant formula.\newlineUsing the values of aa, bb, and cc from Step 11, we get:\newlineD=(12)24(1)(70)D = (-12)^2 - 4(1)(70)
  4. Calculate discriminant: Calculate the discriminant.\newlineD=1444(70)D = 144 - 4(70)\newlineD=144280D = 144 - 280\newlineD=136D = -136

More problems from Solve exponential equations by rewriting the base