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For the following quadratic equation, find the discriminant.

x^(2)+4x+32=2x
Answer:

For the following quadratic equation, find the discriminant.\newlinex2+4x+32=2x x^{2}+4 x+32=2 x \newlineAnswer:

Full solution

Q. For the following quadratic equation, find the discriminant.\newlinex2+4x+32=2x x^{2}+4 x+32=2 x \newlineAnswer:
  1. Rearrange equation: Bring all terms to one side of the equation to get it into standard quadratic form ax2+bx+c=0ax^2 + bx + c = 0. Subtract 2x2x from both sides of the equation x2+4x+32=2xx^2 + 4x + 32 = 2x to get x2+2x+32=0x^2 + 2x + 32 = 0.
  2. Identify coefficients: Identify the coefficients aa, bb, and cc in the standard form of the quadratic equation.\newlineFrom x2+2x+32=0x^2 + 2x + 32 = 0, we have a=1a = 1, b=2b = 2, and c=32c = 32.
  3. Calculate discriminant: Use the discriminant formula D=b24acD = b^2 - 4ac to find the discriminant of the quadratic equation.\newlineSubstitute a=1a = 1, b=2b = 2, and c=32c = 32 into the formula to get D=(2)24(1)(32)D = (2)^2 - 4(1)(32).
  4. Calculate discriminant: Use the discriminant formula D=b24acD = b^2 - 4ac to find the discriminant of the quadratic equation.\newlineSubstitute a=1a = 1, b=2b = 2, and c=32c = 32 into the formula to get D=(2)24(1)(32)D = (2)^2 - 4(1)(32).Calculate the discriminant.\newlineD=4128=124D = 4 - 128 = -124.

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