Q. For the following quadratic equation, find the discriminant.−7x2+54x−231=−4x2Answer:
Bring to Standard Form: First, we need to bring the equation to standard quadratic form ax2+bx+c=0 by combining like terms.−7x2+54x−231=−4x2Add 4x2 to both sides to combine the x2 terms.(−7x2+4x2)+54x−231=0−3x2+54x−231=0
Identify Coefficients: Now that we have the quadratic equation in standard form, we can identify the coefficients a, b, and c.a=−3, b=54, c=−231
Calculate Discriminant: The discriminant of a quadratic equation ax2+bx+c=0 is given by the formula D=b2−4ac. Let's calculate the discriminant using the identified coefficients. D=542−4(−3)(−231)
Find Value: Perform the calculations to find the value of the discriminant.D=2916−4(3)(231)D=2916−2772D=144