For the following quadratic equation, find the discriminant. -7x^(2)+32 x-108=-4x^(2)-4x Answer:

Simplify quadratic equation: First, we need to simplify the given quadratic equation by moving all terms to one side of the equation. -7x^(2) + 32x - 108 = -4x^(2) - 4x Add 4x^(2) to both sides: -7x^(2) + 4x^(2) + 32x - 108 = -4x Add 4x to both sides: -3x^(2) + 36x - 108 = 0Calculate discriminant: Now that we have the simplified quadratic equation in the form ax^(2) + bx + c = 0, we can find the discriminant. The discriminant of a quadratic equation ax^(2) + bx + c is given by the formula D = b^(2) - 4ac. For our equation, a = -3, b = 36, and c = -108.Find discriminant value: Let's calculate the discriminant using the values of a, b, and c. D = b^(2) - 4ac D = (36)^(2) - 4(-3)(-108) D = 1296 - 4(3)(108) D = 1296 - 1296 D = 0

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For the following quadratic equation, find the discriminant.

-7x^(2)+32 x-108=-4x^(2)-4x
Answer:

For the following quadratic equation, find the discriminant. $\newline$ $-7 x^{2}+32 x-108=-4 x^{2}-4 x$ $\newline$ Answer:

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Q. For the following quadratic equation, find the discriminant.

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-7 x^{2}+32 x-108=-4 x^{2}-4 x

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Answer:

Simplify quadratic equation: First, we need to simplify the given quadratic equation by moving all terms to one side of the equation. $\newline$ $-7x^{2} + 32x - 108 = -4x^{2} - 4x$ $\newline$ Add $4x^{2}$ to both sides: $\newline$ $-7x^{2} + 4x^{2} + 32x - 108 = -4x$ $\newline$ Add $4x$ to both sides: $\newline$ $-3x^{2} + 36x - 108 = 0$
Calculate discriminant: Now that we have the simplified quadratic equation in the form $ax^{2} + bx + c = 0$ , we can find the discriminant. The discriminant of a quadratic equation $ax^{2} + bx + c$ is given by the formula $D = b^{2} - 4ac$ . For our equation, $a = -3$ , $b = 36$ , and $c = -108$ .
Find discriminant value: Let's calculate the discriminant using the values of $a$ , $b$ , and $c$ . $D = b^{2} - 4ac$ $D = (36)^{2} - 4(-3)(-108)$ $D = 1296 - 4(3)(108)$ $D = 1296 - 1296$ $D = 0$