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For the following quadratic equation, find the discriminant.

-6x^(2)-8x+29=-7x^(2)-4
Answer:

For the following quadratic equation, find the discriminant.\newline6x28x+29=7x24 -6 x^{2}-8 x+29=-7 x^{2}-4 \newlineAnswer:

Full solution

Q. For the following quadratic equation, find the discriminant.\newline6x28x+29=7x24 -6 x^{2}-8 x+29=-7 x^{2}-4 \newlineAnswer:
  1. Bring to Standard Form: First, we need to bring the quadratic equation to standard form, which is ax2+bx+c=0ax^2 + bx + c = 0. The given equation is 6x28x+29=7x24-6x^2 - 8x + 29 = -7x^2 - 4. Let's move all terms to one side to get it into standard form.
  2. Isolate Zero: Add 7x27x^2 to both sides and add 44 to both sides to isolate the zero on the right side of the equation:\newline6x2+7x28x+29+4=0-6x^2 + 7x^2 - 8x + 29 + 4 = 0
  3. Combine Like Terms: Combine like terms to simplify the equation:\newlinex28x+33=0x^2 - 8x + 33 = 0\newlineNow we have the quadratic equation in standard form, where a=1a = 1, b=8b = -8, and c=33c = 33.
  4. Calculate Discriminant: The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by the formula D=b24acD = b^2 - 4ac. Let's calculate the discriminant using the values of aa, bb, and cc we found.
  5. Substitute Values: Substitute a=1a = 1, b=8b = -8, and c=33c = 33 into the discriminant formula:\newlineD=(8)24(1)(33)D = (-8)^2 - 4(1)(33)
  6. Calculate Result: Calculate the discriminant:\newlineD=644(33)D = 64 - 4(33)\newlineD=64132D = 64 - 132\newlineD=68D = -68

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