Q. For the following quadratic equation, find the discriminant.−6x2−8x+29=−7x2−4Answer:
Bring to Standard Form: First, we need to bring the quadratic equation to standard form, which is ax2+bx+c=0. The given equation is −6x2−8x+29=−7x2−4. Let's move all terms to one side to get it into standard form.
Isolate Zero: Add 7x2 to both sides and add 4 to both sides to isolate the zero on the right side of the equation:−6x2+7x2−8x+29+4=0
Combine Like Terms: Combine like terms to simplify the equation:x2−8x+33=0Now we have the quadratic equation in standard form, where a=1, b=−8, and c=33.
Calculate Discriminant: The discriminant of a quadratic equation ax2+bx+c=0 is given by the formula D=b2−4ac. Let's calculate the discriminant using the values of a, b, and c we found.
Substitute Values: Substitute a=1, b=−8, and c=33 into the discriminant formula:D=(−8)2−4(1)(33)
Calculate Result: Calculate the discriminant:D=64−4(33)D=64−132D=−68