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For the following quadratic equation, find the discriminant.

-6x^(2)-12 x-3=-5x^(2)-4x
Answer:

For the following quadratic equation, find the discriminant.\newline6x212x3=5x24x -6 x^{2}-12 x-3=-5 x^{2}-4 x \newlineAnswer:

Full solution

Q. For the following quadratic equation, find the discriminant.\newline6x212x3=5x24x -6 x^{2}-12 x-3=-5 x^{2}-4 x \newlineAnswer:
  1. Simplify the equation: First, we need to simplify the given quadratic equation by combining like terms on both sides.\newlineThe given equation is:\newline6x212x3=5x24x-6x^2 - 12x - 3 = -5x^2 - 4x\newlineTo simplify, we'll move all terms to one side to get a standard form of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0.\newline6x2+5x212x+4x3=0-6x^2 + 5x^2 - 12x + 4x - 3 = 0\newlineNow, combine like terms.\newline(6x2+5x2)+(12x+4x)3=0(-6x^2 + 5x^2) + (-12x + 4x) - 3 = 0\newline1x28x3=0-1x^2 - 8x - 3 = 0
  2. Move terms to one side: Now that we have the quadratic equation in standard form, we can find the discriminant. The discriminant of a quadratic equation ax2+bx+cax^2 + bx + c is given by the formula:\newlineDiscriminant (D)=b24ac(D) = b^2 - 4ac\newlineFor our equation, a=1a = -1, b=8b = -8, and c=3c = -3.
  3. Combine like terms: Let's calculate the discriminant using the values of aa, bb, and cc.D=(8)24(1)(3)D = (-8)^2 - 4*(-1)*(-3)D=64413D = 64 - 4*1*3D=6412D = 64 - 12D=52D = 52

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