Q. For the following quadratic equation, find the discriminant.−6x2−18x+102=−7x2+2x+2Answer:
Simplify Equation: First, we need to simplify the given quadratic equation by combining like terms on both sides.The given equation is:−6x2−18x+102=−7x2+2x+2
Move Terms to One Side: Now, we will move all terms to one side to set the equation to zero.Add 7x2 to both sides:−6x2+7x2−18x+102=2x+2This simplifies to:x2−18x+102=2x+2
Standard Form: Next, we subtract 2x from both sides and subtract 2 from both sides to get the quadratic equation in standard form:x2−18x−2x+102−2=0This simplifies to:x2−20x+100=0
Find Discriminant: Now that we have the quadratic equation in standard form, we can find the discriminant. The discriminant of a quadratic equation ax2+bx+c=0 is given by the formula:Discriminant (D)=b2−4ac
Calculate Discriminant: For our equation x2−20x+100=0, the coefficients are:a=1, b=−20, and c=100Let's plug these values into the discriminant formula:D=(−20)2−4(1)(100)
Calculate Discriminant: For our equation x2−20x+100=0, the coefficients are:a = 1, b = −20, and c = 100Let's plug these values into the discriminant formula:D=(−20)2−4(1)(100)Calculate the discriminant:D=400−400D=0