Q. For the following quadratic equation, find the discriminant.−4x2+18x+112=2xAnswer:
Rewrite in Standard Form: First, we need to rewrite the quadratic equation in standard form, which is ax2+bx+c=0. −4x2+18x+112=2x Subtract 2x from both sides to get: −4x2+16x+112=0
Identify Coefficients: Now that we have the quadratic equation in standard form, we can identify the coefficients a, b, and c.a=−4, b=16, and c=112
Calculate Discriminant: The discriminant of a quadratic equation ax2+bx+c=0 is given by the formula D=b2−4ac. Let's calculate the discriminant using the identified coefficients: D=(16)2−4(−4)(112)
Perform Calculations: Now, perform the calculations:D=256−4(−4)(112)D=256+1792D=2048
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