For the following quadratic equation, find the discriminant. -3x^(2)+2x-4=x^(2)-6x Answer:

Combine Like Terms: First, we need to combine like terms and bring all terms to one side of the equation to get it into standard quadratic form ax^2 + bx + c = 0. -3x^2 + 2x - 4 = x^2 - 6x -3x^2 - x^2 + 2x + 6x - 4 = 0 -4x^2 + 8x - 4 = 0Identify Coefficients: Now that we have the quadratic equation in standard form, we can identify the coefficients a, b, and c, which are -4, 8, and -4, respectively. a = -4, b = 8, c = -4Calculate Discriminant: The discriminant of a quadratic equation ax^2 + bx + c = 0 is given by the formula D = b^2 - 4ac. Let's calculate the discriminant using the identified coefficients. D = 8^2 - 4(-4)(-4)Perform Calculations: Now, we perform the calculations. D = 64 - 4(16) D = 64 - 64 D = 0

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For the following quadratic equation, find the discriminant.

-3x^(2)+2x-4=x^(2)-6x
Answer:

For the following quadratic equation, find the discriminant. $\newline$ $-3 x^{2}+2 x-4=x^{2}-6 x$ $\newline$ Answer:

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Algebra 2

Composition of linear and quadratic functions: find a value

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Q. For the following quadratic equation, find the discriminant.

\newline

-3 x^{2}+2 x-4=x^{2}-6 x

\newline

Answer:

Combine Like Terms: First, we need to combine like terms and bring all terms to one side of the equation to get it into standard quadratic form $ax^2 + bx + c = 0$ .
$-3x^2 + 2x - 4 = x^2 - 6x$
$-3x^2 - x^2 + 2x + 6x - 4 = 0$
$-4x^2 + 8x - 4 = 0$
Identify Coefficients: Now that we have the quadratic equation in standard form, we can identify the coefficients $a$ , $b$ , and $c$ , which are $-4$ , $8$ , and $-4$ , respectively. $\newline$ $a = -4$ , $b = 8$ , $c = -4$
Calculate Discriminant: The discriminant of a quadratic equation $ax^2 + bx + c = 0$ is given by the formula $D = b^2 - 4ac$ . Let's calculate the discriminant using the identified coefficients. $D = 8^2 - 4(-4)(-4)$
Perform Calculations: Now, we perform the calculations. $\newline$ $D = 64 - 4(16)$ $\newline$ $D = 64 - 64$ $\newline$ $D = 0$