For the following quadratic equation, find the discriminant. -3x^(2)+48 x-125=x^(2)+3 Answer:

Rearrange quadratic equation: Bring all terms to one side of the equation to get a standard form of a quadratic equation ax^2 + bx + c = 0. -3x^2 + 48x - 125 - x^2 - 3 = 0 Combine like terms. (-3x^2 - x^2) + 48x + (-125 - 3) = 0 -4x^2 + 48x - 128 = 0Identify coefficients: Identify the coefficients a, b, and c from the standard form of the quadratic equation. a = -4, b = 48, c = -128Calculate discriminant: Use the discriminant formula for a quadratic equation, which is D = b^2 - 4ac. Substitute the identified coefficients into the formula. D = (48)^2 - 4*(-4)*(-128)Calculate the discriminant. D = 2304 - 4*4*128 D = 2304 - 2048 D = 256

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For the following quadratic equation, find the discriminant.

-3x^(2)+48 x-125=x^(2)+3
Answer:

For the following quadratic equation, find the discriminant. $\newline$ $-3 x^{2}+48 x-125=x^{2}+3$ $\newline$ Answer:

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Algebra 2

Solve exponential equations by rewriting the base

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Q. For the following quadratic equation, find the discriminant.

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-3 x^{2}+48 x-125=x^{2}+3

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Answer:

Rearrange quadratic equation: Bring all terms to one side of the equation to get a standard form of a quadratic equation $ax^2 + bx + c = 0$ . $\newline$ $-3x^2 + 48x - 125 - x^2 - 3 = 0$ $\newline$ Combine like terms. $\newline$ $(-3x^2 - x^2) + 48x + (-125 - 3) = 0$ $\newline$ $-4x^2 + 48x - 128 = 0$
Identify coefficients: Identify the coefficients $a$ , $b$ , and $c$ from the standard form of the quadratic equation. $\newline$ $a = -4$ , $b = 48$ , $c = -128$
Calculate discriminant: Use the discriminant formula for a quadratic equation, which is $D = b^2 - 4ac$ . Substitute the identified coefficients into the formula. $D = (48)^2 - 4*(-4)*(-128)$
Calculate discriminant: Use the discriminant formula for a quadratic equation, which is $D = b^2 - 4ac$ . Substitute the identified coefficients into the formula. $D = (48)^2 - 4*(-4)*(-128)$ Calculate the discriminant. $D = 2304 - 4*4*128$ $D = 2304 - 2048$ $D = 256$