Q. For the following quadratic equation, find the discriminant.3x2+18x−81=4x2Answer:
Rearrange into Standard Form: First, we need to rearrange the quadratic equation into standard form, which is ax2+bx+c=0. We have the equation 3x2+18x−81=4x2. Let's move all terms to one side to get it into standard form. Subtract 4x2 from both sides to get −x2+18x−81=0. Now, we multiply through by −1 to make the x2 term positive, which gives us x2−18x+81=0.
Identify Coefficients: Now that we have the quadratic equation in standard form, we can identify the coefficients a, b, and c. From the equation x2−18x+81=0, we have: a=1, b=−18, and c=81.
Calculate Discriminant: The discriminant of a quadratic equation ax2+bx+c=0 is given by the formula D=b2−4ac. Let's calculate the discriminant using the identified coefficients. D=(−18)2−4(1)(81)
Perform Calculations: Now, we perform the calculations.D=324−4(81)D=324−324D=0
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