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For the following quadratic equation, find the discriminant.

3x^(2)+18 x-81=4x^(2)
Answer:

For the following quadratic equation, find the discriminant.\newline3x2+18x81=4x2 3 x^{2}+18 x-81=4 x^{2} \newlineAnswer:

Full solution

Q. For the following quadratic equation, find the discriminant.\newline3x2+18x81=4x2 3 x^{2}+18 x-81=4 x^{2} \newlineAnswer:
  1. Rearrange into Standard Form: First, we need to rearrange the quadratic equation into standard form, which is ax2+bx+c=0ax^2 + bx + c = 0. We have the equation 3x2+18x81=4x23x^2 + 18x - 81 = 4x^2. Let's move all terms to one side to get it into standard form. Subtract 4x24x^2 from both sides to get x2+18x81=0-x^2 + 18x - 81 = 0. Now, we multiply through by 1-1 to make the x2x^2 term positive, which gives us x218x+81=0x^2 - 18x + 81 = 0.
  2. Identify Coefficients: Now that we have the quadratic equation in standard form, we can identify the coefficients aa, bb, and cc. From the equation x218x+81=0x^2 - 18x + 81 = 0, we have: a=1a = 1, b=18b = -18, and c=81c = 81.
  3. Calculate Discriminant: The discriminant of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0 is given by the formula D=b24acD = b^2 - 4ac. Let's calculate the discriminant using the identified coefficients. D=(18)24(1)(81)D = (-18)^2 - 4(1)(81)
  4. Perform Calculations: Now, we perform the calculations.\newlineD=3244(81)D = 324 - 4(81)\newlineD=324324D = 324 - 324\newlineD=0D = 0

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