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For the following quadratic equation, find the discriminant.

-2x^(2)-12 x+12=-2
Answer:

For the following quadratic equation, find the discriminant.\newline2x212x+12=2 -2 x^{2}-12 x+12=-2 \newlineAnswer:

Full solution

Q. For the following quadratic equation, find the discriminant.\newline2x212x+12=2 -2 x^{2}-12 x+12=-2 \newlineAnswer:
  1. Write Quadratic Equation: Write the quadratic equation in standard form ax2+bx+c=0ax^2 + bx + c = 0. The given equation is 2x212x+12=2-2x^2 - 12x + 12 = -2. To write it in standard form, we need to move all terms to one side of the equation. 2x212x+12+2=0-2x^2 - 12x + 12 + 2 = 0 2x212x+14=0-2x^2 - 12x + 14 = 0
  2. Identify Coefficients: Identify the coefficients aa, bb, and cc from the standard form of the quadratic equation.\newlineIn the equation 2x212x+14=0-2x^2 - 12x + 14 = 0, the coefficient aa is 2-2, the coefficient bb is 12-12, and the coefficient cc is 1414.
  3. Calculate Discriminant: Calculate the discriminant using the formula D=b24acD = b^2 - 4ac. Substitute the values of aa, bb, and cc into the formula. D=(12)24(2)(14)D = (-12)^2 - 4(-2)(14) D=1444(2)(14)D = 144 - 4(-2)(14)
  4. Continue Calculation: Continue the calculation of the discriminant.\newlineD=144(112)D = 144 - (-112)\newlineD=144+112D = 144 + 112\newlineD=256D = 256

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