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For the following equation, evaluate 
(dy)/(dx) when 
x=3.

y=-x^(2)-3
Answer:

For the following equation, evaluate dydx \frac{d y}{d x} when x=3 x=3 .\newliney=x23 y=-x^{2}-3 \newlineAnswer:

Full solution

Q. For the following equation, evaluate dydx \frac{d y}{d x} when x=3 x=3 .\newliney=x23 y=-x^{2}-3 \newlineAnswer:
  1. Identify function: Identify the function to differentiate.\newlineWe are given the function y=x23y = -x^2 - 3 and we need to find its derivative with respect to xx.
  2. Differentiate with respect to x: Differentiate the function with respect to x.\newlineThe derivative of yy with respect to xx, denoted as dydx\frac{dy}{dx}, is found by differentiating each term of the function separately.\newlinedydx=d(x2)dxd(3)dx\frac{dy}{dx} = \frac{d(-x^2)}{dx} - \frac{d(3)}{dx}\newlineThe derivative of x2-x^2 with respect to xx is 2x-2x, and the derivative of a constant like 3-3 is 00.\newlinedydx=2x0\frac{dy}{dx} = -2x - 0\newlinexx00
  3. Evaluate at x=3x=3: Evaluate the derivative at x=3x=3. Substitute x=3x=3 into the derivative to find the slope of the tangent line to the curve at that point. dydx\frac{dy}{dx} at x=3x=3 is 2(3)-2(3). dydx\frac{dy}{dx} at x=3x=3 = 6-6

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