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Find $x$ if $\frac{2(x+1)}{3} = 1$

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Solve linear inequalities

Full solution

Q. Find

x

if

\frac{2(x+1)}{3} = 1

Eliminate Fraction: $\frac{2(x+1)}{3} = 1$ $\newline$ Multiply both sides by $3$ to eliminate the fraction. $\newline$ $3 \times \left[\frac{2(x+1)}{3}\right] = 1 \times 3$ $\newline$ $2(x+1) = 3$
Distribute and Simplify: $2(x+1) = 3$ $\newline$ Distribute the $2$ on the left side. $\newline$ $2\times x + 2\times 1 = 3$ $\newline$ $2x + 2 = 3$
Isolate x Term: $2x + 2 = 3$
Subtract $2$ from both sides to isolate the term with x.
$2x + 2 - 2 = 3 - 2$
$2x = 1$
Solve for x: $2x = 1$ $\newline$ Divide both sides by $2$ to solve for x. $\newline$ $\frac{2x}{2} = \frac{1}{2}$ $\newline$ $x = 0.5$

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