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Find XX and the given problem is x2=72+242x^2 = 7^2 + 24^2

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Q. Find XX and the given problem is x2=72+242x^2 = 7^2 + 24^2
  1. Understand the problem: Understand the problem.\newlineWe need to find the value of XX such that X2=72+242X^2 = 7^2 + 24^2. This is a direct application of the Pythagorean theorem, which states that in a right-angled triangle, the square of the length of the hypotenuse (XX) is equal to the sum of the squares of the lengths of the other two sides (77 and 2424 in this case).
  2. Calculate squares of numbers: Calculate the squares of 77 and 2424. \newline72=497^2 = 49\newline242=57624^2 = 576\newlineNow, add these two values to find the sum of the squares.\newline49+576=62549 + 576 = 625
  3. Set up equation for X2X^2: Set up the equation for X2X^2.X2=72+242X^2 = 7^2 + 24^2X2=625X^2 = 625
  4. Solve for X: Solve for X.\newlineTo find X, we take the square root of both sides of the equation.\newlineX=625X = \sqrt{625}\newlineX=25X = 25

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