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Let’s check out your problem:
Find the zeros of the quadratic function using the
square root
method. What are the
x
x
x
-intercepts of the graph of the function?
\newline
g
(
x
)
=
(
x
−
3
)
2
−
1
g(x)=(x-3)^{2}-1
g
(
x
)
=
(
x
−
3
)
2
−
1
View step-by-step help
Home
Math Problems
Algebra 2
Quadratic equation with complex roots
Full solution
Q.
Find the zeros of the quadratic function using the square root method. What are the
x
x
x
-intercepts of the graph of the function?
\newline
g
(
x
)
=
(
x
−
3
)
2
−
1
g(x)=(x-3)^{2}-1
g
(
x
)
=
(
x
−
3
)
2
−
1
Set Function Equal to Zero:
Set the function equal to zero to find the x-intercepts.
g
(
x
)
=
(
x
−
3
)
2
−
1
=
0
g(x) = (x - 3)^2 - 1 = 0
g
(
x
)
=
(
x
−
3
)
2
−
1
=
0
Add to Isolate Squared Term:
Add
1
1
1
to both sides to isolate the squared term.
\newline
(
x
−
3
)
2
=
1
(x - 3)^2 = 1
(
x
−
3
)
2
=
1
Apply Square Root Method:
Apply the square root method to both sides of the equation to solve for
x
x
x
.
(
x
−
3
)
2
=
±
1
\sqrt{(x - 3)^2} = \pm\sqrt{1}
(
x
−
3
)
2
=
±
1
Simplify Square Roots:
Simplify the square root of the squared term and the square root of
1
1
1
.
x
−
3
=
±
1
x - 3 = \pm 1
x
−
3
=
±
1
Solve for x:
Solve for x by adding
3
3
3
to both sides of the equation.
\newline
x
=
3
±
1
x = 3 \pm 1
x
=
3
±
1
Write Solutions:
Write the two solutions for
x
x
x
.
x
=
3
+
1
x = 3 + 1
x
=
3
+
1
or
x
=
3
−
1
x = 3 - 1
x
=
3
−
1
Simplify Expressions:
Simplify both expressions to find the
x
x
x
-intercepts.
x
=
4
x = 4
x
=
4
or
x
=
2
x = 2
x
=
2
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)
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?
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Question
3
⋅
(
3
+
20
i
)
=
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⋅
(
3
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i
)
=
\newline
Your answer should be a complex number in the form
a
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b
i
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a
+
bi
where
a
a
a
and
b
b
b
are real numbers.
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(
35
−
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i
)
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(
13
+
25
i
)
=
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(
35
−
23
i
)
+
(
13
+
25
i
)
=
\newline
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(
a
+
b
i
)
(a+b i)
(
a
+
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)
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