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Find the 
y-coordinate of the 
y-intercept of the polynomial function defined below.

f(x)=-x(5x+3)(x-4)^(2)
Answer:

Find the y y -coordinate of the y y -intercept of the polynomial function defined below.\newlinef(x)=x(5x+3)(x4)2 f(x)=-x(5 x+3)(x-4)^{2} \newlineAnswer:

Full solution

Q. Find the y y -coordinate of the y y -intercept of the polynomial function defined below.\newlinef(x)=x(5x+3)(x4)2 f(x)=-x(5 x+3)(x-4)^{2} \newlineAnswer:
  1. Evaluate at x=0x = 0: To find the yy-coordinate of the yy-intercept of the function, we need to evaluate the function at x=0x = 0, because the yy-intercept occurs where the graph of the function crosses the yy-axis, and the xx-coordinate of any point on the yy-axis is 00.
  2. Substitute x=0x = 0: Substitute x=0x = 0 into the function f(x)=x(5x+3)(x4)2f(x) = -x(5x+3)(x-4)^{2}.\newlinef(0)=0(50+3)(04)2f(0) = -0(5\cdot0+3)(0-4)^{2}
  3. Simplify expression: Simplify the expression by performing the multiplication and exponentiation.\newlinef(0)=0(0+3)(4)2f(0) = -0(0+3)(-4)^{2}\newlinef(0)=0(3)(16)f(0) = -0(3)(16)
  4. Final result: Since any number multiplied by zero is zero, the entire expression simplifies to 00.f(0)=0f(0) = 0
  5. Find y-intercept: The y-coordinate of the y-intercept is the value of f(0)f(0), which we have found to be 00.

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