Bytelearn - cat image with glassesAI tutor

Welcome to Bytelearn!

Let’s check out your problem:

Find the 
y-coordinate of the 
y-intercept of the polynomial function defined below.

f(x)=-(x+1)(x-4)^(2)
Answer:

Find the y y -coordinate of the y y -intercept of the polynomial function defined below.\newlinef(x)=(x+1)(x4)2 f(x)=-(x+1)(x-4)^{2} \newlineAnswer:

Full solution

Q. Find the y y -coordinate of the y y -intercept of the polynomial function defined below.\newlinef(x)=(x+1)(x4)2 f(x)=-(x+1)(x-4)^{2} \newlineAnswer:
  1. Evaluate Function at x=0x=0: To find the yy-coordinate of the yy-intercept of the function f(x)f(x), we need to evaluate the function at x=0x=0, because the yy-intercept occurs where the graph of the function crosses the yy-axis, and the xx-coordinate of any point on the yy-axis is 00.\newlineCalculation: yy00
  2. Substitute x=0x=0: Now we substitute x=0x=0 into the function and simplify.\newlineCalculation: f(0)=(1)(4)2=(1)(16)=16f(0) = -(1)(-4)^2 = -(1)(16) = -16
  3. Find Y-Coordinate: The yy-coordinate of the yy-intercept is the value we found by substituting x=0x=0 into the function, which is 16-16.

More problems from Reflections of functions