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Find the volume of a pyramid with a square base, where the side length of the base is 17.7m and the height of the pyramid is 9.4m. Round your answer to the nearest tenth of a cubic meter. Answer: m^(3)

Find the volume of a pyramid with a square base, where the side length of the base is 17.7 m 17.7 \mathrm{~m} and the height of the pyramid is 9.4 m 9.4 \mathrm{~m} . Round your answer to the nearest tenth of a cubic meter.\newlineAnswer: m3 \mathrm{m}^{3}

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Q. Find the volume of a pyramid with a square base, where the side length of the base is 17.7 m 17.7 \mathrm{~m} and the height of the pyramid is 9.4 m 9.4 \mathrm{~m} . Round your answer to the nearest tenth of a cubic meter.\newlineAnswer: m3 \mathrm{m}^{3}
  1. Identify Formula: Identify the formula for the volume of a pyramid with a square base. The formula is Volume=13×base area×height\text{Volume} = \frac{1}{3} \times \text{base area} \times \text{height}. The base area for a square is side length2\text{side length}^2.
  2. Calculate Base Area: Calculate the area of the base. Since the base is a square with a side length of 17.7 m17.7\,\text{m}, the area is 17.7 m×17.7 m17.7\,\text{m} \times 17.7\,\text{m}.\newlineArea = 17.7 m×17.7 m=313.29 m217.7\,\text{m} \times 17.7\,\text{m} = 313.29\,\text{m}^2
  3. Apply Volume Formula: Apply the volume formula using the base area and the height of the pyramid. The height is given as 9.4 m9.4\,\text{m}. \newlineVolume = (1/3)×313.29 m2×9.4 m(1/3) \times 313.29\,\text{m}^2 \times 9.4\,\text{m}
  4. Perform Multiplication: Perform the multiplication to find the volume.\newlineVolume = (13)×313.29 m2×9.4 m=1043.633 m33(\frac{1}{3}) \times 313.29\,\text{m}^2 \times 9.4\,\text{m} = \frac{1043.633\,\text{m}^3}{3}
  5. Divide for Final Volume: Divide by 33 to get the final volume.\newlineVolume = 1043.633 m33≈347.877 m3\frac{1043.633\,\text{m}^3}{3} \approx 347.877\,\text{m}^3
  6. Round Answer: Round the answer to the nearest tenth of a cubic meter.\newlineVolume ≈347.9 m3\approx 347.9\,\text{m}^3

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