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Find the volume of a pyramid with a square base, where the perimeter of the base is 13.2 in and the height of the pyramid is 
6.6in. Round your answer to the nearest tenth of a cubic inch.
Answer: in 
^(3)

Find the volume of a pyramid with a square base, where the perimeter of the base is 1313.22 in\text{in} and the height of the pyramid is 6.6 6.6 in\mathrm{in} . Round your answer to the nearest tenth of a cubic inch.\newlineAnswer: in\text{in} 3 ^{3}

Full solution

Q. Find the volume of a pyramid with a square base, where the perimeter of the base is 1313.22 in\text{in} and the height of the pyramid is 6.6 6.6 in\mathrm{in} . Round your answer to the nearest tenth of a cubic inch.\newlineAnswer: in\text{in} 3 ^{3}
  1. Find Side Length: First, we need to find the length of one side of the square base. Since the perimeter of a square is four times the length of one side, we can find the side length by dividing the perimeter by 44.\newlinePerimeter of base = 13.2in13.2\,\text{in}\newlineSide length = Perimeter // 44\newlineSide length = 13.2in/413.2\,\text{in} / 4\newlineSide length = 3.3in3.3\,\text{in}
  2. Calculate Base Area: Next, we calculate the area of the square base using the side length we just found.\newlineArea of base = Side length ×\times Side length\newlineArea of base = 3.33.3 in ×\times 3.33.3 in\newlineArea of base = 10.8910.89 in2^2
  3. Find Volume: Now, we can find the volume of the pyramid. The volume of a pyramid is one-third the product of the base area and the height.\newlineVolume = (13)×Base area×Height(\frac{1}{3}) \times \text{Base area} \times \text{Height}\newlineVolume = (13)×10.89 in2×6.6 in(\frac{1}{3}) \times 10.89 \text{ in}^2 \times 6.6 \text{ in}\newlineVolume = (13)×71.874 in3(\frac{1}{3}) \times 71.874 \text{ in}^3\newlineVolume = 2323.958958 \text{ in}^33
  4. Round to Nearest Tenth: Finally, we round the volume to the nearest tenth of a cubic inch.\newlineVolume 24.0\approx 24.0 in3^3

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