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Find the volume of a pyramid with a square base, where the area of the base is 
19.9m^(2) and the height of the pyramid is 
21.5m. Round your answer to the nearest tenth of a cubic meter.
Answer: 
m^(3)

Find the volume of a pyramid with a square base, where the area of the base is 19.9 m2 19.9 \mathrm{~m}^{2} and the height of the pyramid is 21.5 m 21.5 \mathrm{~m} . Round your answer to the nearest tenth of a cubic meter.\newlineAnswer: m3 \mathrm{m}^{3}

Full solution

Q. Find the volume of a pyramid with a square base, where the area of the base is 19.9 m2 19.9 \mathrm{~m}^{2} and the height of the pyramid is 21.5 m 21.5 \mathrm{~m} . Round your answer to the nearest tenth of a cubic meter.\newlineAnswer: m3 \mathrm{m}^{3}
  1. Identify formula for volume: Identify the formula for the volume of a pyramid.\newlineThe volume of a pyramid is given by the formula V=13×base area×heightV = \frac{1}{3} \times \text{base area} \times \text{height}.\newlineHere, the base area (AA) is 19.9m219.9 \, \text{m}^2 and the height (hh) is 21.5m21.5 \, \text{m}.
  2. Substitute given values: Substitute the given values into the formula. \newlineVolume = (13)×19.9m2×21.5m(\frac{1}{3}) \times 19.9 \, \text{m}^2 \times 21.5 \, \text{m}
  3. Perform multiplication: Perform the multiplication to find the volume.\newlineVolume = (13)×19.9×21.5(\frac{1}{3}) \times 19.9 \times 21.5\newlineVolume = (13)×426.85m3(\frac{1}{3}) \times 426.85 \, \text{m}^3
  4. Calculate final volume: Calculate the final volume by dividing by 33. \newlineVolume = 426.85m3/3426.85 \, \text{m}^3 / 3 \newlineVolume = 142.2833m3142.2833\ldots \, \text{m}^3
  5. Round answer: Round the answer to the nearest tenth of a cubic meter.\newlineVolume 142.3\approx 142.3 m3^3

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