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Find the value of 
x that solves the equation 
ln(x-1)=2-ln 2.
Answer:

Find the value of x x that solves the equation ln(x1)=2ln2 \ln (x-1)=2-\ln 2 .\newlineAnswer:

Full solution

Q. Find the value of x x that solves the equation ln(x1)=2ln2 \ln (x-1)=2-\ln 2 .\newlineAnswer:
  1. Understand and Isolate Variable Term: Understand the equation and isolate the variable term.\newlineWe have the equation ln(x1)=2ln2\ln(x-1) = 2 - \ln 2. To solve for xx, we need to isolate the term containing xx on one side of the equation.
  2. Combine Right Side Terms: Use properties of logarithms to combine the terms on the right side of the equation.\newlineWe can use the property of logarithms that states ln(a)ln(b)=ln(ab)\ln(a) - \ln(b) = \ln\left(\frac{a}{b}\right) to combine the terms on the right side of the equation. This gives us ln(x1)=ln(e22)\ln(x-1) = \ln\left(\frac{e^2}{2}\right).
  3. Equate Arguments of Logarithms: Since the natural logarithm function ln\ln is the inverse of the exponential function with base ee, we can equate the arguments of the logarithms to solve for xx. If ln(x1)=ln(e22)\ln(x-1) = \ln(\frac{e^2}{2}), then x1=e22x-1 = \frac{e^2}{2}.
  4. Solve for x: Solve for x by adding 11 to both sides of the equation.x=e22+1x = \frac{e^2}{2} + 1
  5. Calculate Final Value: Calculate the value of e2/2+1e^2/2 + 1. We know that ee is approximately 2.718282.71828, so e2e^2 is approximately 7.389067.38906. Dividing this by 22 gives us approximately 3.694533.69453. Adding 11 to this gives us x4.69453x \approx 4.69453.

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