Q. Find the value of x that solves the equation ln(x−1)+21ln16=ln2.Answer: x=
Simplify equation: First, we need to simplify the equation using properties of logarithms. The equation is ln(x−1)+21ln16=ln2. We know that 21ln16 can be simplified because ln16 is the natural log of 2 to the power of 4, so 21ln16 is the same as ln1621 or ln4.
Rewrite with simplification: Now we rewrite the equation using the simplification from the previous step: ln(x−1)+ln4=ln2.
Combine left side: Using the property of logarithms that lna+lnb=ln(ab), we can combine the left side of the equation: ln((x−1)⋅4)=ln2.
Simplify left side: Simplify the left side of the equation to get ln(4x−4)=ln2.
Set up equation: Since the natural log function is one-to-one, if ln(4x−4)=ln2, then 4x−4 must be equal to 2. We can now solve for x by setting 4x−4 equal to 2.
Isolate x term: Add 4 to both sides of the equation to isolate the term with x: 4x−4+4=2+4, which simplifies to 4x=6.
Solve for x: Divide both sides of the equation by 4 to solve for x: 44x=46, which simplifies to x=46 or x=1.5.
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