Q. Find the value of c so that the polynomial p(x) is divisible by (x+2).p(x)=4x3+cx2+x+2c=
Using the Remainder Theorem: To determine the value of c that makes the polynomial p(x) divisible by (x+2), we can use polynomial long division or synthetic division. However, a simpler method is to use the Remainder Theorem, which states that if a polynomial f(x) is divisible by (x−k), then f(k)=0. In this case, since we want p(x) to be divisible by (x+2), we set x=−2 and solve for p(−2)=0.
Substituting x=−2: Substitute x=−2 into the polynomial p(x)=4x3+cx2+x+2.p(−2)=4(−2)3+c(−2)2+(−2)+2
Calculating p(−2): Calculate the value of p(−2).p(−2)=4(−8)+c(4)−2+2p(−2)=−32+4c−2+2p(−2)=−32+4c
Setting p(−2)=0: Since we want p(x) to be divisible by (x+2), we set p(−2)=0.−32+4c=0
Solving for c: Solve for c.4c=32c=432c=8
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