Find the square. Simplify your answer. (z - 1)^2 ______

Special Case Identification: (z - 1)^2 Which special case applies here? (z - 1)^2 is in the form of (a - b)^2. Special case: (a - b)^2 = a^2 - 2ab + b^2Identify a and b: (z - 1)^2 Identify the values of a and b. Compare (z - 1)^2 with (a - b)^2. a = z b = 1Apply Binomial Square: We found: a = z b = 1 Apply square of a binomial to expand (z - 1)^2. (a - b)^2 = a^2 - 2ab + b^2 (z - 1)^2 = z^2 - 2(z)(1) + 1^2Simplify Expression: Simplify z^2 - 2(z)(1) + 1^2. z^2 - 2(z)(1) + 1^2 = z^2 - 2z + 1

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Find the square. Simplify your answer. $\newline$ $(z - 1)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(z - 1)^2

Special Case Identification: z - $1)^ $2$ (\newline$Which special case applies here? $\newline$ z - \(1)^ $2$ \ is in the form of a - b)^\(2\. $\newline$ Special case: a - b)^\(2 = a^ $2$ - $2$ ab + b^ $2$ \
Identify $a$ and $b$ : $(z - 1)^2$ $\newline$ Identify the values of $a$ and $b$ . $\newline$ Compare $(z - 1)^2$ with $(a - b)^2$ . $\newline$ $a = z$ $\newline$ $b = 1$
Apply Binomial Square: We found: $\newline$ $a = z$ $\newline$ $b = 1$ $\newline$ Apply square of a binomial to expand $(z - 1)^2$ . $\newline$ $(a - b)^2 = a^2 - 2ab + b^2$ $\newline$ $(z - 1)^2 = z^2 - 2(z)(1) + 1^2$
Simplify Expression: Simplify $z^2 - 2(z)(1) + 1^2$ . $\newline$ $z^2 - 2(z)(1) + 1^2$ $\newline$ = $z^2 - 2z + 1$