Find the square. Simplify your answer. (x - 4)^2 ______

Identify binomial and formula: Identify the binomial to be squared and the special case formula to use. The given expression is (x - 4)^2, which is a binomial squared. The special case formula for the square of a binomial is (a - b)^2 = a^2 - 2ab + b^2. Here, a = x and b = 4.Apply special case formula: Apply the special case formula to the given binomial. Using the formula (a - b)^2 = a^2 - 2ab + b^2, we substitute a with x and b with 4. (x - 4)^2 = x^2 - 2(x)(4) + 4^2Perform multiplication and simplify: Perform the multiplication and simplify the expression. x^2 - 2(x)(4) + 4^2 = x^2 - 8x + 16

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Find the square. Simplify your answer. $\newline$ $(x - 4)^2$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(x - 4)^2

Identify binomial and formula: Identify the binomial to be squared and the special case formula to use. $\newline$ The given expression is $(x - 4)^2$ , which is a binomial squared. $\newline$ The special case formula for the square of a binomial is $(a - b)^2 = a^2 - 2ab + b^2$ . $\newline$ Here, $a = x$ and $b = 4$ .
Apply special case formula: Apply the special case formula to the given binomial. $\newline$ Using the formula $(a - b)^2 = a^2 - 2ab + b^2$ , we substitute $a$ with $x$ and $b$ with $4$ . $\newline$ $(x - 4)^2 = x^2 - 2(x)(4) + 4^2$
Perform multiplication and simplify: Perform the multiplication and simplify the expression. $\newline$ $x^2 - 2(x)(4) + 4^2$ $\newline$ = $x^2 - 8x + 16$