Find the square. Simplify your answer. (k - 4)^2 ______

Identify special case: Identify the special case for (k - 4)^2. (k - 4)^2 is in the form of (a - b)^2. Special case: (a - b)^2 = a^2 - 2ab + b^2Identify values of a and b: Identify the values of a and b. Compare (k - 4)^2 with (a - b)^2. a = k b = 4Apply binomial formula: Apply the square of a binomial formula to expand (k - 4)^2. (a - b)^2 = a^2 - 2ab + b^2 (k - 4)^2 = k^2 - 2(k)(4) + 4^2Simplify expression: Simplify k^2 - 2(k)(4) + 4^2. k^2 - 2(k)(4) + 4^2 = k^2 - 8k + 16

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Find the square. Simplify your answer. $\newline$ $(k - 4)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(k - 4)^2

Identify special case: Identify the special case for $(k - 4)^2$ . $(k - 4)^2$ is in the form of $(a - b)^2$ . Special case: $(a - b)^2 = a^2 - 2ab + b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(k - 4)^2$ with $(a - b)^2$ . $a = k$ $b = 4$
Apply binomial formula: Apply the square of a binomial formula to expand $(k - 4)^2$ . $\newline$ $(a - b)^2 = a^2 - 2ab + b^2$ $\newline$ $(k - 4)^2 = k^2 - 2(k)(4) + 4^2$
Simplify expression: Simplify $k^2 - 2(k)(4) + 4^2$ . $\newline$ $k^2 - 2(k)(4) + 4^2$ $\newline$ $= k^2 - 8k + 16$