Find the square. Simplify your answer. (4z - 2)^2 ______

Identify Binomial & Formula: Identify the binomial to be squared and the special case formula. The given expression is (4z - 2)^2, which is a binomial squared. The special case formula for the square of a binomial (a - b)^2 is a^2 - 2ab + b^2.Identify a and b: Identify the values of a and b in the binomial. In the expression (4z - 2)^2, a is 4z and b is 2. We will use these values in the special case formula.Apply Special Case Formula: Apply the special case formula to expand (4z - 2)^2. Using the formula (a - b)^2 = a^2 - 2ab + b^2, we substitute a with 4z and b with 2: (4z - 2)^2 = (4z)^2 - 2*(4z)*2 + 2^2Simplify Expression: Simplify the expression by performing the calculations. (4z)^2 - 2*(4z)*2 + 2^2 = 16z^2 - 16z + 4

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(4z - 2)^2

Identify Binomial & Formula: Identify the binomial to be squared and the special case formula. $\newline$ The given expression is $(4z - 2)^2$ , which is a binomial squared. The special case formula for the square of a binomial $(a - b)^2$ is $a^2 - 2ab + b^2$ .
Identify $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial. $\newline$ In the expression $(4z - 2)^2$ , $a$ is $4z$ and $b$ is $2$ . We will use these values in the special case formula.
Apply Special Case Formula: Apply the special case formula to expand $(4z - 2)^2$ . Using the formula $(a - b)^2 = a^2 - 2ab + b^2$ , we substitute $a$ with $4z$ and $b$ with $2$ : $(4z - 2)^2 = (4z)^2 - 2\cdot(4z)\cdot2 + 2^2$
Simplify Expression: Simplify the expression by performing the calculations. $\newline$ $(4z)^2 - 2\times(4z)\times2 + 2^2 = 16z^2 - 16z + 4$