Find the square. Simplify your answer. (4s - 2)^2 ______

Identify values of a and b: Identify the values of a and b in the binomial (4s - 2)^2. Comparing (4s - 2)^2 with (a - b)^2, we find that: a = 4s b = 2Apply binomial square formula: Apply the square of a binomial formula to expand (4s - 2)^2. Using the values of a and b identified in the previous step, we get: (4s - 2)^2 = (4s)^2 - 2*(4s)*2 + 2^2Simplify the expression: Simplify the expression (4s)^2 - 2*(4s)*2 + 2^2. (4s)^2 - 2*(4s)*2 + 2^2 = (4s * 4s) - (2 * 4 * 2)s + (2 * 2) = 16s^2 - 16s + 4

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Find the square. Simplify your answer. $\newline$ $(4s - 2)^2$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(4s - 2)^2

Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial $(4s - 2)^2$ . Comparing $(4s - 2)^2$ with $(a - b)^2$ , we find that: $a = 4s$ $b = 2$
Apply binomial square formula: Apply the square of a binomial formula to expand $(4s - 2)^2$ . $\newline$ Using the values of $a$ and $b$ identified in the previous step, we get: $\newline$ $(4s - 2)^2 = (4s)^2 - 2\times(4s)\times2 + 2^2$
Simplify the expression: Simplify the expression $(4s)^2 - 2\times(4s)\times2 + 2^2.$ (\(4s)^ $2$ - $2$ \times( $4$ s)\times $2$ + $2$ ^ $2$ = ( $4$ s \times $4$ s) - ( $2$ \times $4$ \times $2$ )s + ( $2$ \times $2$ ) = $16$ s^ $2$ - $16$ s + $4$