Find the square. Simplify your answer. (4q - 4)^2 ______

Identify binomial and formula: Identify the binomial to be squared and the special case formula. The given expression is (4q - 4)^2, which is in the form of (a - b)^2. Special case: (a - b)^2 = a^2 - 2ab + b^2Identify values of a and b: Identify the values of a and b. Compare (4q - 4)^2 with (a - b)^2. a = 4q b = 4Apply binomial square formula: Apply the square of a binomial formula to expand (4q - 4)^2. (a - b)^2 = a^2 - 2ab + b^2 (4q - 4)^2 = (4q)^2 - 2(4q)(4) + (4)^2Simplify expression: Simplify (4q)^2 - 2(4q)(4) + (4)^2. (4q)^2 - 2(4q)(4) + (4)^2 = (4q * 4q) - (2 * 4 * 4)q + 4 * 4 = 16q^2 - 32q + 16

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Find the square. Simplify your answer. $\newline$ $(4q - 4)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(4q - 4)^2

Identify binomial and formula: Identify the binomial to be squared and the special case formula. $\newline$ The given expression is $(4q - 4)^2$ , which is in the form of $(a - b)^2$ . $\newline$ Special case: $(a - b)^2 = a^2 - 2ab + b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(4q - 4)^2$ with $(a - b)^2$ . $a = 4q$ $b = 4$
Apply binomial square formula: Apply the square of a binomial formula to expand $(4q - 4)^2$ . $\newline$ $(a - b)^2 = a^2 - 2ab + b^2$ $\newline$ $(4q - 4)^2 = (4q)^2 - 2(4q)(4) + (4)^2$
Simplify expression: Simplify (\(4q)^ $2$ - $2$ ( $4$ q)( $4$ ) + ( $4$ )^ $2$ .\
(\(4q)^ $2$ - $2$ ( $4$ q)( $4$ ) + ( $4$ )^ $2$ \
= ( $4$ q \times $4$ q) - ( $2$ \times $4$ \times $4$ )q + $4$ \times $4$ \
= $16$ q^ $2$ - $32$ q + $16$