Find the square. Simplify your answer. (4b - 2)^2 ______

Identify binomial and formula: Identify the binomial to be squared and the special case formula to use. The given binomial is (4b - 2), and we need to square it. The special case formula for the square of a binomial is (a - b)^2 = a^2 - 2ab + b^2.Identify values of a and b: Identify the values of a and b in the binomial (4b - 2). In the binomial (4b - 2), a is 4b and b is 2.Apply binomial square formula: Apply the square of a binomial formula to expand (4b - 2)^2. Using the formula (a - b)^2 = a^2 - 2ab + b^2, we get: (4b - 2)^2 = (4b)^2 - 2*(4b)*2 + (2)^2Simplify each term: Simplify each term in the expansion. (4b)^2 = 16b^2 (since 4b * 4b = 16b^2) 2*(4b)*2 = 16b (since 2 * 4b * 2 = 16b) (2)^2 = 4 (since 2 * 2 = 4) So, (4b - 2)^2 = 16b^2 - 16b + 4

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Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

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(4b - 2)^2

Identify binomial and formula: Identify the binomial to be squared and the special case formula to use. $\newline$ The given binomial is $(4b - 2)$ , and we need to square it. The special case formula for the square of a binomial is $(a - b)^2 = a^2 - 2ab + b^2$ .
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial $(4b - 2)$ . In the binomial $(4b - 2)$ , $a$ is $4b$ and $b$ is $2$ .
Apply binomial square formula: Apply the square of a binomial formula to expand $(4b - 2)^2$ . Using the formula $(a - b)^2 = a^2 - 2ab + b^2$ , we get: $(4b - 2)^2 = (4b)^2 - 2\cdot(4b)\cdot2 + (2)^2$
Simplify each term: Simplify each term in the expansion. $\newline$ $(4b)^2 = 16b^2$ (since $4b \times 4b = 16b^2$ ) $\newline$ $2\times(4b)\times2 = 16b$ (since $2 \times 4b \times 2 = 16b$ ) $\newline$ $(2)^2 = 4$ (since $2 \times 2 = 4$ ) $\newline$ So, $(4b - 2)^2 = 16b^2 - 16b + 4$