Find the square. Simplify your answer. (3u - 4)^2 ______

Identify binomial and formula: Identify the binomial to be squared and the special case formula. The given expression is (3u - 4)^2, which is in the form of (a - b)^2. Special case: (a - b)^2 = a^2 - 2ab + b^2Identify values of a and b: Identify the values of a and b. Compare (3u - 4)^2 with (a - b)^2. a = 3u b = 4Apply binomial square formula: Apply the square of a binomial formula to expand (3u - 4)^2. (a - b)^2 = a^2 - 2ab + b^2 (3u - 4)^2 = (3u)^2 - 2(3u)(4) + 4^2Simplify expression: Simplify (3u)^2 - 2(3u)(4) + 4^2. (3u)^2 - 2(3u)(4) + 4^2 = (3u * 3u) - (2 * 3 * 4)u + 4 * 4 = 9u^2 - 24u + 16

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Find the square. Simplify your answer. $\newline$ $(3u - 4)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(3u - 4)^2

Identify binomial and formula: Identify the binomial to be squared and the special case formula. $\newline$ The given expression is $(3u - 4)^2$ , which is in the form of $(a - b)^2$ . $\newline$ Special case: $(a - b)^2 = a^2 - 2ab + b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . Compare $(3u - 4)^2$ with $(a - b)^2$ . $a = 3u$ $b = 4$
Apply binomial square formula: Apply the square of a binomial formula to expand $(3u - 4)^2$ . $\newline$ $(a - b)^2 = a^2 - 2ab + b^2$ $\newline$ $(3u - 4)^2 = (3u)^2 - 2(3u)(4) + 4^2$
Simplify expression: Simplify $(3u)^2 - 2(3u)(4) + 4^2.$ $(3u)^2 - 2(3u)(4) + 4^2$ $= (3u \cdot 3u) - (2 \cdot 3 \cdot 4)u + 4 \cdot 4$ $= 9u^2 - 24u + 16$