Find the square. Simplify your answer. (3u + 2)^2 ______

Identify binomial and formula: Identify the binomial to be squared and the special case formula to use. The binomial to be squared is (3u + 2), and the special case formula for the square of a binomial (a + b)^2 is a^2 + 2ab + b^2.Determine values of a and b: Determine the values of a and b in the binomial. In the expression (3u + 2), a is 3u and b is 2.Apply binomial formula: Apply the square of a binomial formula to expand (3u + 2)^2. Using the formula (a + b)^2 = a^2 + 2ab + b^2, we get (3u + 2)^2 = (3u)^2 + 2*(3u)*(2) + (2)^2.Simplify each term: Simplify each term in the expansion. (3u)^2 = 9u^2, 2*(3u)*(2) = 12u, and (2)^2 = 4. So, (3u + 2)^2 = 9u^2 + 12u + 4.

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Find the square. Simplify your answer. $\newline$ $(3u + 2)^2$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(3u + 2)^2

Identify binomial and formula: Identify the binomial to be squared and the special case formula to use. $\newline$ The binomial to be squared is $3u + 2$ , and the special case formula for the square of a binomial $a + b)^2\ is \$a^2 + 2ab + b^2$ .
Determine values of a and b: Determine the values of a and b in the binomial. $\newline$ In the expression $(3u + 2)$ , $a$ is $3u$ and $b$ is $2$ .
Apply binomial formula: Apply the square of a binomial formula to expand $(3u + 2)^2$ . Using the formula $(a + b)^2 = a^2 + 2ab + b^2$ , we get $(3u + 2)^2 = (3u)^2 + 2\cdot(3u)\cdot(2) + (2)^2$ .
Simplify each term: Simplify each term in the expansion. $\newline$ $(3u)^2 = 9u^2$ , $2\cdot(3u)\cdot(2) = 12u$ , and $(2)^2 = 4$ . $\newline$ So, $(3u + 2)^2 = 9u^2 + 12u + 4$ .