Find the square. Simplify your answer. (3g + 4)^2 ______

Identify special case: Identify the special case for squaring a binomial. The expression (3g + 4)^2 is in the form of (a + b)^2. Special case: (a + b)^2 = a^2 + 2ab + b^2Identify values of a and b: Identify the values of a and b in the expression (3g + 4)^2. Compare (3g + 4)^2 with (a + b)^2. a = 3g b = 4Apply binomial square formula: Apply the square of a binomial formula to expand (3g + 4)^2. (a + b)^2 = a^2 + 2ab + b^2 (3g + 4)^2 = (3g)^2 + 2(3g)(4) + 4^2Simplify expression: Simplify the expression (3g)^2 + 2(3g)(4) + 4^2. (3g)^2 + 2(3g)(4) + 4^2 = (3g * 3g) + (2 * 3g * 4) + (4 * 4) = 9g^2 + 24g + 16

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Find the square. Simplify your answer. $\newline$ $(3g + 4)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(3g + 4)^2

Identify special case: Identify the special case for squaring a binomial. $\newline$ The expression $(3g + 4)^2$ is in the form of $(a + b)^2$ . $\newline$ Special case: $(a + b)^2 = a^2 + 2ab + b^2$
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ in the expression $(3g + 4)^2$ . Compare $(3g + 4)^2$ with $(a + b)^2$ . $a = 3g$ $b = 4$
Apply binomial square formula: Apply the square of a binomial formula to expand $(3g + 4)^2$ . $(a + b)^2 = a^2 + 2ab + b^2$ $(3g + 4)^2 = (3g)^2 + 2(3g)(4) + 4^2$
Simplify expression: Simplify the expression $(3g)^2 + 2(3g)(4) + 4^2.$ $(3g)^2 + 2(3g)(4) + 4^2$ $= (3g \cdot 3g) + (2 \cdot 3g \cdot 4) + (4 \cdot 4)$ $= 9g^2 + 24g + 16$