Find the square. Simplify your answer. (3c - 1)^2 ______

Identify Binomial and Formula: Identify the binomial to be squared and the special case formula. The given expression is (3c - 1)^2, which is a binomial squared. The special case formula for the square of a binomial is (a - b)^2 = a^2 - 2ab + b^2.Identify a and b: Identify the values of a and b in the binomial. In the expression (3c - 1)^2, a is 3c and b is 1.Apply Binomial Formula: Apply the square of a binomial formula to expand (3c - 1)^2. Using the formula (a - b)^2 = a^2 - 2ab + b^2, we get: (3c - 1)^2 = (3c)^2 - 2*(3c)*1 + 1^2Simplify Expression: Simplify the expanded expression. (3c)^2 - 2*(3c)*1 + 1^2 = 9c^2 - 6c + 1

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Find the square. Simplify your answer. $\newline$ $(3c - 1)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(3c - 1)^2

Identify Binomial and Formula: Identify the binomial to be squared and the special case formula. $\newline$ The given expression is $(3c - 1)^2$ , which is a binomial squared. The special case formula for the square of a binomial is $(a - b)^2 = a^2 - 2ab + b^2$ .
Identify $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial. $\newline$ In the expression $(3c - 1)^2$ , $a$ is $3c$ and $b$ is $1$ .
Apply Binomial Formula: Apply the square of a binomial formula to expand $(3c - 1)^2$ . Using the formula $(a - b)^2 = a^2 - 2ab + b^2$ , we get: $(3c - 1)^2 = (3c)^2 - 2\cdot(3c)\cdot1 + 1^2$
Simplify Expression: Simplify the expanded expression. $\newline$ $(3c)^2 - 2\times(3c)\times 1 + 1^2$ $\newline$ = $9c^2 - 6c + 1$