Find the square. Simplify your answer. (3b - 2)^2 ______

Identify values of a and b: Identify the values of a and b. In the expression (3b - 2)^2, a is 3b and b is 2.Apply binomial square formula: Apply the square of a binomial formula to expand (3b - 2)^2. Using the identity (a - b)^2 = a^2 - 2ab + b^2, we get: (3b - 2)^2 = (3b)^2 - 2*(3b)*2 + (2)^2Simplify terms in expansion: Simplify each term in the expansion. (3b)^2 = 9b^2 (since 3b * 3b = 9b^2) -2*(3b)*2 = -12b (since -2 * 3b * 2 = -12b) (2)^2 = 4 (since 2 * 2 = 4)Combine simplified terms: Combine the simplified terms to get the final answer. (3b - 2)^2 = 9b^2 - 12b + 4

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Find the square. Simplify your answer. $\newline$ $(3b - 2)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(3b - 2)^2

Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ . In the expression $(3b - 2)^2$ , $a$ is $3b$ and $b$ is $2$ .
Apply binomial square formula: Apply the square of a binomial formula to expand $(3b - 2)^2$ . Using the identity $(a - b)^2 = a^2 - 2ab + b^2$ , we get: $(3b - 2)^2 = (3b)^2 - 2\cdot(3b)\cdot2 + (2)^2$
Simplify terms in expansion: Simplify each term in the expansion. $\newline$ $(3b)^2 = 9b^2$ (since $3b \times 3b = 9b^2$ ) $\newline$ $-2\times(3b)\times2 = -12b$ (since $-2 \times 3b \times 2 = -12b$ ) $\newline$ $(2)^2 = 4$ (since $2 \times 2 = 4$ )
Combine simplified terms: Combine the simplified terms to get the final answer. $\newline$ $(3b - 2)^2 = 9b^2 - 12b + 4$