Find the square. Simplify your answer. (2x - 4)^2 ______

Identify values of a and b: Identify the values of a and b in the binomial (2x - 4). In the expression (2x - 4)^2, a is 2x and b is 4.Apply binomial square formula: Apply the square of a binomial formula to expand (2x - 4)^2. Using the formula (a - b)^2 = a^2 - 2ab + b^2, we get: (2x - 4)^2 = (2x)^2 - 2*(2x)*4 + 4^2Simplify expansion terms: Simplify each term in the expansion. (2x)^2 = 4x^2 (since 2x * 2x = 4x^2) 2*(2x)*4 = 16x (since 2 * 2x * 4 = 16x) 4^2 = 16 (since 4 * 4 = 16)Combine simplified terms: Combine the simplified terms to get the final answer. (2x - 4)^2 = 4x^2 - 16x + 16

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Find the square. Simplify your answer. $\newline$ $(2x - 4)^2$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(2x - 4)^2

Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial $(2x - 4)$ . In the expression $(2x - 4)^2$ , $a$ is $2x$ and $b$ is $4$ .
Apply binomial square formula: Apply the square of a binomial formula to expand $(2x - 4)^2$ . Using the formula $(a - b)^2 = a^2 - 2ab + b^2$ , we get: $(2x - 4)^2 = (2x)^2 - 2\cdot(2x)\cdot4 + 4^2$
Simplify expansion terms: Simplify each term in the expansion. $\newline$ $(2x)^2 = 4x^2$ (since $2x \times 2x = 4x^2$ ) $\newline$ $2\times(2x)\times4 = 16x$ (since $2 \times 2x \times 4 = 16x$ ) $\newline$ $4^2 = 16$ (since $4 \times 4 = 16$ )
Combine simplified terms: Combine the simplified terms to get the final answer. $\newline$ $(2x - 4)^2 = 4x^2 - 16x + 16$