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Find the square. Simplify your answer.\newline(2t+2)2(2t + 2)^2

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Q. Find the square. Simplify your answer.\newline(2t+2)2(2t + 2)^2
  1. Identify binomial and formula: Identify the binomial to be squared and the special case formula to use.\newlineThe binomial to be squared is (2t+2)(2t + 2), and it is in the form of (a+b)2(a + b)^2.\newlineSpecial case: (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2
  2. Determine values of aa and bb: Determine the values of aa and bb in the binomial (2t+2)(2t + 2). Comparing (2t+2)(2t + 2) with (a+b)(a + b), we find that a=2ta = 2t and b=2b = 2.
  3. Apply binomial square formula: Apply the square of a binomial formula to expand (2t+2)2(2t + 2)^2. Using the formula (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2, we get: (2t+2)2=(2t)2+2(2t)(2)+22(2t + 2)^2 = (2t)^2 + 2(2t)(2) + 2^2
  4. Simplify expression: Simplify the expression (2t)2+2(2t)(2)+22.(2t)^2 + 2(2t)(2) + 2^2.(2t)2+2(2t)(2)+22(2t)^2 + 2(2t)(2) + 2^2=(2t2t)+(222)t+22= (2t \cdot 2t) + (2 \cdot 2 \cdot 2)t + 2 \cdot 2=4t2+8t+4= 4t^2 + 8t + 4

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