Find the square. Simplify your answer. (2s - 1)^2 ______

Identify values of a and b: Identify the values of a and b in the binomial (2s - 1)^2. In this case, a = 2s and b = 1.Apply binomial square formula: Apply the square of a binomial formula to expand (2s - 1)^2. Using the formula (a - b)^2 = a^2 - 2ab + b^2, we get: (2s - 1)^2 = (2s)^2 - 2*(2s)*1 + 1^2Simplify each term: Simplify each term in the expansion. (2s)^2 = 4s^2 (since 2s * 2s = 4s^2) -2*(2s)*1 = -4s (since 2 * 2s * 1 = 4s) 1^2 = 1 (since 1 * 1 = 1)Combine simplified terms: Combine the simplified terms to get the final answer. (2s - 1)^2 = 4s^2 - 4s + 1

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Find the square. Simplify your answer. $\newline$ $(2s - 1)^2$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(2s - 1)^2

Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial $(2s - 1)^2$ . In this case, $a = 2s$ and $b = 1$ .
Apply binomial square formula: Apply the square of a binomial formula to expand $(2s - 1)^2$ . Using the formula $(a - b)^2 = a^2 - 2ab + b^2$ , we get: $(2s - 1)^2 = (2s)^2 - 2\cdot(2s)\cdot1 + 1^2$
Simplify each term: Simplify each term in the expansion. $\newline$ $(2s)^2 = 4s^2$ (since $2s \times 2s = 4s^2$ ) $\newline$ $-2\times(2s)\times1 = -4s$ (since $2 \times 2s \times 1 = 4s$ ) $\newline$ $1^2 = 1$ (since $1 \times 1 = 1$ )
Combine simplified terms: Combine the simplified terms to get the final answer. $\newline$ $(2s - 1)^2 = 4s^2 - 4s + 1$