Find the square. Simplify your answer. (2k - 1)^2 ______

Identify binomial and formula: Identify the binomial to be squared and the special case formula to use. The given expression is (2k - 1)^2, which is in the form of (a - b)^2. Special case: (a - b)^2 = a^2 - 2ab + b^2Identify values of a and b: Identify the values of a and b in the binomial. Compare (2k - 1)^2 with (a - b)^2. a = 2k b = 1Apply binomial square formula: Apply the square of a binomial formula to expand (2k - 1)^2. (2k - 1)^2 = (2k)^2 - 2(2k)(1) + (1)^2Simplify each term: Simplify each term in the expansion. (2k)^2 - 2(2k)(1) + (1)^2 = (2k * 2k) - (2 * 2 * k) + (1 * 1) = 4k^2 - 4k + 1

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Find the square. Simplify your answer. $\newline$ $(2k - 1)^2$

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Math Problems

Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(2k - 1)^2

Identify binomial and formula: Identify the binomial to be squared and the special case formula to use. $\newline$ The given expression is \(2k - $1$ )^ $2$ \, which is in the form of a - b)^\(2\. $\newline$ Special case: a - b)^\(2 = a^ $2$ - $2$ ab + b^ $2$ \
Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial. Compare $(2k - 1)^2$ with $(a - b)^2$ . $a = 2k$ $b = 1$
Apply binomial square formula: Apply the square of a binomial formula to expand $(2k - 1)^2$ . $(2k - 1)^2 = (2k)^2 - 2(2k)(1) + (1)^2$
Simplify each term: Simplify each term in the expansion. $\newline$ $(2k)^2 - 2(2k)(1) + (1)^2$ $\newline$ = $(2k \cdot 2k) - (2 \cdot 2 \cdot k) + (1 \cdot 1)$ $\newline$ = $4k^2 - 4k + 1$