Find the square. Simplify your answer. (2h + 4)^2 ______

Identify values of a and b: Identify the values of a and b in the binomial (2h + 4)^2. In this case, a = 2h and b = 4.Apply binomial square formula: Apply the square of a binomial formula to expand (2h + 4)^2. Using the formula (a + b)^2 = a^2 + 2ab + b^2, we get: (2h + 4)^2 = (2h)^2 + 2*(2h)*(4) + 4^2.Simplify each term: Simplify each term in the expansion. (2h)^2 = 4h^2 (since 2h * 2h = 4h^2), 2*(2h)*(4) = 16h (since 2 * 2h * 4 = 16h), 4^2 = 16 (since 4 * 4 = 16).Combine simplified terms: Combine the simplified terms to get the final answer. (2h + 4)^2 = 4h^2 + 16h + 16.

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Find the square. Simplify your answer. $\newline$ $(2h + 4)^2$

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Algebra 1

Multiply two binomials: special cases

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Q. Find the square. Simplify your answer.

\newline

(2h + 4)^2

Identify values of $a$ and $b$ : Identify the values of $a$ and $b$ in the binomial $(2h + 4)^2$ . In this case, $a = 2h$ and $b = 4$ .
Apply binomial square formula: Apply the square of a binomial formula to expand $(2h + 4)^2$ . Using the formula $(a + b)^2 = a^2 + 2ab + b^2$ , we get: $(2h + 4)^2 = (2h)^2 + 2\cdot(2h)\cdot(4) + 4^2$ .
Simplify each term: Simplify each term in the expansion. $\newline$ $(2h)^2 = 4h^2$ (since $2h \times 2h = 4h^2$ ), $\newline$ $2\times(2h)\times(4) = 16h$ (since $2 \times 2h \times 4 = 16h$ ), $\newline$ $4^2 = 16$ (since $4 \times 4 = 16$ ).
Combine simplified terms: Combine the simplified terms to get the final answer. $\newline$ $(2h + 4)^2 = 4h^2 + 16h + 16$ .