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Find the square. Simplify your answer.\newline(2g+2)2(2g + 2)^2

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Q. Find the square. Simplify your answer.\newline(2g+2)2(2g + 2)^2
  1. Identify binomial and formula: Identify the binomial to be squared and the special case formula to use.\newlineThe binomial to be squared is (2g+2)(2g + 2), and it is in the form of (a+b)2(a + b)^2.\newlineSpecial case: (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2
  2. Identify values of aa and bb: Identify the values of aa and bb in the binomial (2g+2)(2g + 2). Comparing (2g+2)(2g + 2) with (a+b)(a + b), we find that a=2ga = 2g and b=2b = 2.
  3. Apply binomial square formula: Apply the square of a binomial formula to expand (2g+2)2(2g + 2)^2. Using the formula (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2, we get: (2g+2)2=(2g)2+2(2g)(2)+(2)2(2g + 2)^2 = (2g)^2 + 2(2g)(2) + (2)^2
  4. Simplify expression: Simplify the expression (2g)2+2(2g)(2)+(2)2.(2g)^2 + 2(2g)(2) + (2)^2.(2g)2+2(2g)(2)+(2)2=(2g×2g)+(2×2×2)g+(2×2)(2g)^2 + 2(2g)(2) + (2)^2 = (2g \times 2g) + (2 \times 2 \times 2)g + (2 \times 2)=4g2+8g+4= 4g^2 + 8g + 4

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